7.Binomial Theorem
easy

${16^{th}}$ term in the expansion of ${(\sqrt x - \sqrt y )^{17}}$ is

A

$136x{y^7}$

B

$136xy$

C

$ - 136x{y^{15/2}}$

D

$ - 136x{y^2}$

Solution

(c) ${T_{16}} = {\,^{17}}{C_{15}}{(\sqrt x )^2}{( – \sqrt y )^{15}}$

$ = – \frac{{17 \times 16}}{{2 \times 1}} \times x{y^{15/2}} = – 136x{y^{15/2}}$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.