In the figure, A B C D is a unit square. A ci | vedclass

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Question

(d)

Given, $A B C D$ is a square

$A B=C D=A D=B C=1$

$A C$ is tangent of circle

$\angle O A C =90^{\circ}$

$\angle C A D =45^{\circ}$

Vedclass · Accepted Answer

$\frac{6-\pi}{4}$

Vedclass · Answer

(d)

Given, $A B C D$ is a square

$A B=C D=A D=B C=1$

$A C$ is tangent of circle

$\angle O A C =90^{\circ}$

$\angle C A D =45^{\circ}$

$\angle O A D =45^{\circ}$

$O A =\sqrt{2}$

$	herefore$ Area of shaded region

$=$ Area of square $+$ Area of

$	riangle A O D-$ Area of sector

$=1+\frac{1}{2} 	imes 1-\frac{45}{360} 	imes(\sqrt{2})^2 \cdot \pi$

$=1+\frac{1}{2}-\frac{\pi}{4}-\frac{3}{2}-\frac{\pi}{4}-\frac{6-\pi}{4}$

In the figure, $A B C D$ is a unit square. A circle is drawn with centre $O$ on the extended line $C D$ and passing through $A$. If the diagonal $A C$ is tangent to the circle, then the area of the shaded region is

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