Gujarati
Hindi
1. Electric Charges and Fields
normal

In the figure shown, the potential difference between points $A$ and $B$ is......$V$

A

$10$

B

$30$

C

$7.5$

D

None

Solution

Potential difference across $\mathrm{MN}=30 \mathrm{\,V}$

$\mathrm{V}_{\mathrm{m}}-\mathrm{V}_{\mathrm{N}}=30 \mathrm{\,V}$

$\therefore $ potential difference across each capaictor

$=\frac{30}{3}=10 \mathrm{\,V}$

$\therefore \mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=10 \mathrm{\,V}$

Standard 12
Physics

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