In figure shown block B moves down with a velocity 10 m/s . velocity of A in position shown is .....

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4-1.Newton's Laws of Motion

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In the figure shown the block $B$ moves down with a velocity $10 m/s$. The velocity of $A$ in the position shown is ......... $m/s$

A

$12.5$

B

$25$

C

$6.25$

D

none of these

Solution

(B) The velocity of $A$ is $25 m / s$.

Velocity of string is twice the velocity of B

$v_{l}=2 \times 10=20 m / s$

To calculate, velocity of A as function of velocity of string, use following equation

$x^{2}+y^{2}=L^{2}$

$2 x d x / d t=2 L d l / d t$

$d x / d t=\sec 37^{\circ} d l / d t$

$v_{A}=5 / 4 \times 20=25 m / s$

Standard 11

Physics

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