In the following reaction $_{12}M{g^{24}}{ + _2}H{e^4}{ \to _{14}}S{i^X}{ + _0}{n^1},X$ is
$28$
$27$
$26$
$22$
The mass of an $\alpha$-particle is
The ratio of radii of nuclei $_{13}A{l^{27}}$ and $_{52}{X^A}$ is $3 : 5$. The number of neutrons in the nuclei of $X$ will be
Ratio of nuclear radii of ${ }^{135} Cs$ to ${ }^{40} Ca$ is
Two nucleons are at a separation of $1 \times {10^{ - 15}}m$. The net force between them is ${F_1}$, if both are neutrons, ${F_2}$ if both are protons and ${F_3}$ if one is a proton and other is a neutron. In such a case
A nucleus represented by the symbol ${ }_{Z}^{ A } X$ has