The radius of germanium (Ge) nuclide is measu | vedclass

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Question

Nuclear radii $R=R_{0}(A)^{1 / 3}$

where $R_{0} \approx 1.2 \mathrm{Fm}$

or $R \propto(A)^{1 / 3}$

$	herefore \,\,\frac{{{R_{{	ext{Bc}}}}}}

Vedclass · Accepted Answer

$72$

Vedclass · Answer

Nuclear radii $R=R_{0}(A)^{1 / 3}$

where $R_{0} \approx 1.2 \mathrm{Fm}$

or $R \propto(A)^{1 / 3}$

$	herefore \,\,\frac{{{R_{{	ext{Bc}}}}}}{{{R_{{	ext{Ge}}}}}} = \frac{{{{(9)}^{1/3}}}}{{{{(A)}^{1/3}}}}{	ext{ }}$ or $\frac{{{R_{{	ext{Be}}}}}}{{2{R_{{	ext{Be}}}}}} = \frac{{{{(9)}^{1/3}}}}{{{{(A)}^{1/3}}}}$

( $\because $ given ${R_{Ge}}\, = \,2{R_{Be}}$) 

or, $(A)^{1 / 3}=2 	imes(9)^{1 / 3}$ or, $A=2^{3} 	imes 9=8 	imes 9=72$

$	herefore$ The number of nucleons in $Ge$ is $72$

The radius of germanium $(Ge)$ nuclide is measured to be twice the radius of ${}_4^9Be$ . The number of nucleons in $Ge$ are

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