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4-2.Friction
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આપેલી પરિસ્થિતિ માટે $F$ નું મહત્તમ મૂલ્ય શું હોઈ શકે જેથી બંને બ્લોક વચ્ચે કોઈ સાપેક્ષ ગતિ ન હોય.
A$\mu m_1 g$
B$\mu\left(m_1+m_2\right) g$
C$\mu m_1 g\left(\frac{m_1}{m_2}+1\right)$
DZero
Solution
(c)
(c)
$\left(m_1+m_2\right) a_{\text {max }}=f$
$\rightarrow F=\mu N$
$N=m_1 g$
$m_2 a_{\text {max }}=\mu m_1 g$
$a_{\text {max }}=\mu \frac{m_1}{m_2} g$
$F=\left(m_1+m_2\right) \mu \frac{m_1}{m_2} g$
$= m_2\left(\frac{m_1}{m_2}+1\right) \mu \frac{m_1}{m_2} g$
$F =\mu m_1\left(\frac{m_1}{m_2}+1\right)$
(c)
$\left(m_1+m_2\right) a_{\text {max }}=f$
$\rightarrow F=\mu N$
$N=m_1 g$
$m_2 a_{\text {max }}=\mu m_1 g$
$a_{\text {max }}=\mu \frac{m_1}{m_2} g$
$F=\left(m_1+m_2\right) \mu \frac{m_1}{m_2} g$
$= m_2\left(\frac{m_1}{m_2}+1\right) \mu \frac{m_1}{m_2} g$
$F =\mu m_1\left(\frac{m_1}{m_2}+1\right)$
Standard 11
Physics
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