In the given figure electric field at center $O$ due to section $AB$ of uniformly charged ring is $\overrightarrow E$. What will be electric field at $O$ due to section $ACB$ ?
$\overrightarrow E$
$ -\overrightarrow E$
$\frac{{\overrightarrow E }}{2}$
$ -\frac{{\overrightarrow E }}{2}$
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