1. Electric Charges and Fields
hard

For a uniformly charged ring of radius $R$, the electric field on its axis has the largest magnitude at a distance $h$ from its centre. Then value of $h$ is

A

$\frac{R}{{\sqrt 5 }}$

B

$\frac{R}{{\sqrt 2 }}$

C

$R$

D

$R\sqrt 2 $

(JEE MAIN-2019)

Solution

Electric field $E=\frac{k Q x}{\left(x^{2}+R^{2}\right)^{3 / 2}}$

For maxima $\frac{d E}{d x}=0$

After solving we get, $\left(x \pm \frac{\mathrm{R}}{\sqrt{2}}\right)$

Standard 12
Physics

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