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1. Electric Charges and Fields
hard
For a uniformly charged ring of radius $R$, the electric field on its axis has the largest magnitude at a distance $h$ from its centre. Then value of $h$ is
A
$\frac{R}{{\sqrt 5 }}$
B
$\frac{R}{{\sqrt 2 }}$
C
$R$
D
$R\sqrt 2 $
(JEE MAIN-2019)
Solution
Electric field $E=\frac{k Q x}{\left(x^{2}+R^{2}\right)^{3 / 2}}$
For maxima $\frac{d E}{d x}=0$
After solving we get, $\left(x \pm \frac{\mathrm{R}}{\sqrt{2}}\right)$
Standard 12
Physics
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