In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be (Given area of plate $=A$ )
$\frac{25}{6} \frac{{K} \varepsilon_{0} {A}}{{d}}$
$\frac{15}{34} \frac{{K\varepsilon}_{0} {A}}{{d}}$
$\frac{15}{6} \frac{{K} \varepsilon_{0} {A}}{{d}}$
$\frac{9}{6} \frac{{K} \varepsilon_{0} {A}}{{d}}$
What are polar and non-polar molecules ?
On which the extant of polarisation depend ?
If the dielectric constant and dielectric strength be denoted by $k$ and $x$ respectively, then a material suitable for use as a dielectric in a capacitor must have
A parallel plate capacitor is filled by a dielectric whose relative permittivity varies with the applied voltage $(U )$ as $\varepsilon = \alpha U$ where $\alpha = 2{V^{ - 1}}$. A similar capacitor with no dielectric is charged to ${U_0} = 78\,V$. It is then connected to the uncharged capacitor with the dielectric. Find the final voltage on the capacitors.
A parallel plate air capacitor has a capacitance of $100\,\mu F$. The plates are at a distance $d$ apart. If a slab of thickness $t(t \le d)$and dielectric constant $5$ is introduced between the parallel plates, then the capacitance will be.......$\mu F$