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2. Electric Potential and Capacitance
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Two parallel plate capacitors of capacity $C$ and $3\,C$ are connected in parallel combination and charged to a potential difference $18\,V$. The battery is then disconnected and the space between the plates of the capacitor of capacity $C$ is completely filled with a material of dielectric constant $9$. The final potential difference across the combination of capacitors will be $V$
A
$5$
B
$4$
C
$6$
D
$1$
(JEE MAIN-2022)
Solution

Initial charge on $C =18\,CV$
initial charge on $3 C =54\,CV$
Let final common potential difference $= V ^{\prime}$
$9\,CV ^{\prime}+3\,CV ^{\prime}=18\,CV +54\,CV$
$12\,CV ^{\prime}=72\,CV \Rightarrow V ^{\prime}=6 V$
Standard 12
Physics
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