3. Coordinate Geometry
easy

In which quadrant or on which axis do each of the points $(-\, 2,\, 4)$, $(3, \,-\, 1)$, $(-\, 1,\, 0)$, $(1,\, 2)$ and $(-\, 3, \,-\, 5)$ lie ? Verify your answer by locating them on the Cartesian plane.

Option A
Option B
Option C
Option D

Solution

In the point $(-\,2,\,4),$ the abscissa is negative and the ordinate is positive.

$\because (-,\,+)$ belongs to $2nd$ quadrant.

$\therefore $ $(-\,2,\,4)$ lies in the second quadrant.

The point $(3,\,-1)$ is having $+ ve$ abscissa and $-\,ve$ ordinate.

$\therefore \,(3,\,-\,1)$ lies in the $4 th$ quadrant.

The point $(-\,1,\,0)$ is having $(- \,ve )$ abscissa and ordinate on the $x$ -axis.

$\therefore$ The point $(-\,1,\,0)$ lies on the negative $x$ -axis.

The point $(1,\,2)$ is having the $x$ – coordiante as well as $y$ – coordinate $+\,v e .$

$\therefore$ Point $(1,\,2)$ lies in the list quadrant.

The point $(-\,3,\,-\,5)$ is having the abscissa as well as ordinate negative.

$\therefore$ Point $(-\,3,\,-\,5)$ lies in the $3 rd$ quadrant.

These points are plotted in the Cartesian plane as shown in the following figure as $A\, (-\,2,\,4)$ ; $B \,(3,\,-\,1)$ $C\, (-\,1,\,0) $;  $D \,(1,\,2)$ and $E \,(-\,3,\,-\,5)$.

Standard 9
Mathematics

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