Ionisation constant of $CH_3COOH$ is $1.7 \times 10^{-5}$ and concentration of $H^+$ ions is $3.4 \times 10^{-4}$. Then find out initial concentration of $CH_3COOH$ Molecules
Ionisation constant of $CH_3COOH$ is $1.7 \times 10^{-5}$ and concentration of $H^+$ ions is $3.4 \times 10^{-4}$. Then find out initial concentration of $CH_3COOH$ Molecules
- A
$3.4 \times {10^{ - 4}}$
- B
$3.4 \times {10^{ - 3}}$
- C
$6.8 \times {10^{ - 4}}$
- D
$6.8 \times {10^{ - 3}}$
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