It is not convenient to use a spherical Gaussian surface to electric field due to an electric dipole

English

Gujarati

Hindi

1. Electric Charges and Fields

easy

It is not convenient to use a spherical Gaussian surface to find the electric field due to an electric dipole using Gauss’s theorem because

A

Gauss’s law fails in this case

B

This problem does not have spherical symmetry

C

Coulomb’s law is more fundamental than Gauss’s law

D

Spherical Gaussian surface will alter the dipole moment

Solution

(b)

Standard 12

Physics

Share

Similar Questions

The electric field intensity at $P$ and $Q$, in the shown arrangement, are in the ratio

medium

A few electric field lines for a system of two charges $Q_1$ and $Q_2$ fixed at two different points on the $x$ -axis are shown in the figure. These lines suggest that:-

medium

The spatial distribution of the electric field due to charges $(A, B)$ is shown in figure. Which one of the following statements is correct

normal

An electric field $\overrightarrow{\mathrm{E}}=(2 \mathrm{xi}) \mathrm{NC}^{-1}$ exists in space. $\mathrm{A}$ cube of side $2 \mathrm{~m}$ is placed in the space as per figure given below. The electric flux through the cube is ……………… $\mathrm{Nm}^2 / \mathrm{C}$

hard

(JEE MAIN-2024)

If a spherical conductor comes out from the closed surface of the sphere then total flux emitted from the surface will be

easy