Electric field intensity at P and Q , in shown arrangement, are in ratio

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1. Electric Charges and Fields

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The electric field intensity at $P$ and $Q$, in the shown arrangement, are in the ratio

A

$1: 2$

B

$2: 1$

C

$1: 1$

D

$4: 3$

Solution

(c)

$E_p=\frac{k q}{r^2} \quad \dots (i)$

$E_Q=\frac{k q}{(2 r)^2}+\frac{k \cdot 3 q}{(2 r)^2}$

$=\frac{k q}{4 r^2}+\frac{k \cdot 3 q}{4 r^2}$

$=\frac{k q}{r^2} \quad \dots (ii)$

$E_P: E_Q=1: 1$

Standard 12

Physics

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