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10-2. Parabola, Ellipse, Hyperbola
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Latus rectum of ellipse $4{x^2} + 9{y^2} - 8x - 36y + 4 = 0$ is
A
$8\over3$
B
$4\over3$
C
$\frac{{\sqrt 5 }}{3}$
D
$16\over3$
Solution
(a) The ellipse is $4{(x – 1)^2} + 9{(y – 2)^2} = 36$
Therefore, latus rectum$ = \frac{{2{b^2}}}{a} = \frac{{2.4}}{3} = \frac{8}{3}$.
Standard 11
Mathematics
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