Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

Latus rectum of ellipse $4{x^2} + 9{y^2} - 8x - 36y + 4 = 0$ is

A

$8\over3$

B

$4\over3$

C

$\frac{{\sqrt 5 }}{3}$

D

$16\over3$

Solution

(a) The ellipse is $4{(x – 1)^2} + 9{(y – 2)^2} = 36$

Therefore, latus rectum$ = \frac{{2{b^2}}}{a} = \frac{{2.4}}{3} = \frac{8}{3}$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.