Solution set of 8x equiv 6(bmod 14),,x ∈ Z , are

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2.Relations and Functions

hard

The solution set of $8x \equiv 6(\bmod 14),\,x \in Z$, are

A

$[8] \cup [6]$

B

$[8] \cup [14]$

C

$[6] \cup [13]$

D

$[8] \cup [6] \cup [13]$

Solution

(c) $8x – 6 = 14P,\,(x \in Z)$

==> $x = \frac{1}{8}[14P + 6]$, $(x \in Z)$

==> $x$ = $\frac{1}{4}(7P + 3)$

==> $x = 6, 13, 20, 27, 34, 41, 48,.….$

$\therefore $ Solution set $= {6, 20, 34, 48,…}$ $\cup$ ${13, 27, 41, ….} $= $[6] \cup [13]$,

where $[6], [13]$ are equivalence classes of $6$ and $13$ respectively.

Standard 11

Mathematics

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