Let $U=\{1,2,3,4,5,6,7,8,9\}, A=\{1,2,3,4\}, B=\{2,4,6,8\}$ and $C=\{3,4,5,6\} .$ Find

$(B-C)^{\prime}$

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$A=\{1,2,3,4\}$

$B=\{2,4,6,8\}$

$C=\{3,4,5,6\}$

$B-C=\{2,8\}$

$\therefore(B-C)^{\prime}=\{1,3,4,5,6,7,9\}$

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