3 and 4 .Determinants and Matrices
hard

माना $P =\left[\begin{array}{ccc}3 & -1 & -2 \\ 2 & 0 & \alpha \\ 3 & -5 & 0\end{array}\right]$ है, जबकि $\alpha \in R$ है। माना $Q =\left[ q _{ ij }\right]$ एक आव्यूह है, जिसके लिए $PQ = kI _{3}$, किसी शून्येतर, $k \in K$ के लिए, है। यदि $q _{23}=-\frac{ k }{8}$ तथा $| Q |=\frac{ k ^{2}}{2}$ है, तो $\alpha^{2}+ k ^{2}$ बराबर है

A

$17$

B

$21$

C

$13$

D

$19$

(JEE MAIN-2021)

Solution

$PQ = kI$

$| P | \cdot| Q |= k ^{3}$

$\Rightarrow| P |=2 k \neq 0 \Rightarrow P$ is an invertible matrix

$\because PQ = kI$

$\therefore Q=k P^{-1} I$

$\therefore Q=\frac{\text { adj.P }}{2}$

$\because q _{23}=-\frac{ k }{8}$

$\therefore \frac{-(3 \alpha+4)}{2}=-\frac{ k }{8} \Rightarrow k =4$

$\therefore| P |=2 k \Rightarrow k =10+6 \alpha \ldots( i )$

Put value of $k$ in (i).. we get $\alpha=-1$

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.