Let $\left(\frac{n}{k}\right)=\frac{n !}{k !(n-k) !}$. Then the sum $\frac{1}{2^{10}} \sum \limits_{ k =0}^{10}\left(\frac{10}{ k }\right) k ^2$, lies in the interval

  • [KVPY 2021]
  • A

    $(26,27)$

  • B

    $(27,28)$

  • C

    $(28,29)$

  • D

    $(29,30)$

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