Let vec{A}=2 hat{i}-3 hat{j}+4 hat{k} and vec | vedclass

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Question

(b)

$\vec{A}=2 \hat{\imath}-3 \hat{\jmath}+4 \hat{k}$

$\vec{B}=4 \hat{\imath}+\hat{\jmath}+2 \hat{k}$

$|\vec{A} 	imes \vec{B}|=$ ?

$|\vec

Vedclass · Accepted Answer

$2 \sqrt{110}$

Vedclass · Answer

(b)

$\vec{A}=2 \hat{\imath}-3 \hat{\jmath}+4 \hat{k}$

$\vec{B}=4 \hat{\imath}+\hat{\jmath}+2 \hat{k}$

$|\vec{A} 	imes \vec{B}|=$ ?

$|\vec{A} 	imes \vec{B}|=? \quad\left|\begin{array}{ccc}\hat{\imath} & \hat{\jmath} & \hat{k} \ 2 & -3 & 4 \ 4 & 1 & 2\end{array}ight|$

$=\hat{\imath}(-6-4)-\hat{\jmath}(4-16)+k(2+12)$

$=-10 \hat{\imath}+12 \hat{\jmath}+14 \hat{k}$

$|\vec{A} 	imes \vec{B}|=\sqrt{(-10)^2+(12)^2+(14)^2}$

$=\sqrt{\frac{100+144+196}{\sqrt{440}}}$

$=\sqrt{440}=2 \sqrt{110}$

Colum $I$	Colum $II$
$(A)$ $(A+B)$	$(p)$ North-east
$(B)$ $(A-B)$	$(q)$ Vertically upwards
$(C)$ $(A \times B)$	$(r)$ Vertically downwards
$(D)$ $(A \times B) \times(A \times B)$	$(s)$ None

Let $\vec{A}=2 \hat{i}-3 \hat{j}+4 \hat{k}$ and $\vec{B}=4 \hat{i}+j+2 \hat{k}$ then $|\vec{A} \times \vec{B}|$ is equal to ...................

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