- Home
- Standard 11
- Mathematics
1.Set Theory
medium
જો $n(U) = 700,\,n(A) = 200,\,n(B) = 300$ અને $n(A \cap B) = 100,$ તો $n({A^c} \cap {B^c}) = $
A
$400$
B
$600$
C
$300$
D
$200$
Solution
(c) $n({A^c} \cap {B^c}) = n[(A \cup B)^c] $ = $n(U) – n(A \cup B)$
= $n(U) – [n(A) + n(B) – n(A \cap B)]$
$= 700 -[200 + 300 -100] = 300.$
Standard 11
Mathematics