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1.Set Theory
easy
જો $U =\{1,2,3,4,5,6,7,8,9\}, A =\{2,4,6,8\}$ અને $B =\{2,3,5,7\}$ હોય, તો $(A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}$ ચકાસો.
Option A
Option B
Option C
Option D
Solution
$U=\{1,2,3,4,5,6,7,8,9\}$
$A=\{2,4,6,8\}, B=\{2,3,5,7\}$
$(A \cup B)^{\prime}=\{2,3,4,5,6,7,8\}^{\prime}=\{1,9\}$
$A^{\prime} \cap B^{\prime}=\{1,3,5,7,9\} \cap\{1,4,6,8,9\}=\{1,9\}$
$\therefore(A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}$
Standard 11
Mathematics