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1.Set Theory
easy
Let $A$ and $B$ be subsets of a set $X$. Then
A
$A - B = A \cup B$
B
$A - B = A \cap B$
C
$A - B = {A^c} \cap B$
D
$A - B = A \cap {B^c}$
Solution
(d) $A – B = \{ x:x \in A$ and $x\not \in B\} $
$ = \{ x:x \in A $ and $x \in {B^c}\} = A \cap {B^c}$.
Standard 11
Mathematics
