Let A and B be subsets of a set X . Then

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1.Set Theory

easy

Let $A$ and $B$ be subsets of a set $X$. Then

A

$A - B = A \cup B$

B

$A - B = A \cap B$

C

$A - B = {A^c} \cap B$

D

$A - B = A \cap {B^c}$

Solution

(d) $A – B = \{ x:x \in A$ and $x\not \in B\} $

$ = \{ x:x \in A $ and $x \in {B^c}\} = A \cap {B^c}$.

Standard 11

Mathematics

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