Let A = {1, 2, 3, 4, 5}; B = {2, 3, 6, 7} . Then number of elements in (A × B) cap (B ×

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2.Relations and Functions

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Let $A = \{1, 2, 3, 4, 5\}; B = \{2, 3, 6, 7\}$. Then the number of elements in $(A × B) \cap (B × A)$ is

A

$18$

B

$6$

C

$4$

D

$0$

Solution

(c) Here $A$ and $B$ sets having $2$ elements in common, so $A \times B$ and $B \times A$ have ${2^2}$ i.e., $4$ elements in common.

Hence, $n\,[(A \times B) \cap (B \times A)] = 4$.

Standard 11

Mathematics

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