If $A=\{-1,1\},$ find $A \times A \times A.$
If is known that for any non-empty set $A, A \times A \times A$ is defined as
$A \times A \times A=\{(a, b, c): a, b, c \in A\}$
It is given that $A=\{-1,1\}$
$\therefore A \times A \times A=\left\{\begin{array}{l}(-1-1,-1),(-1,-1,1),(-1,1,-1),(-1,1,1), \\ (1,-1,-1),(1,-1,1),(1,1,-1),(1,1,1)\end{array}\right\}$
If $A = \{ a,\,b\} ,\,B = \{ c,\,d\} ,\,C = \{ d,\,e\} ,\,$ then $\{ (a,\,c),\,(a,\,d),\,(a,\,e),\,(b,\,c),\,(b,\,d),\,(b,\,e)\} $ is equal to
State whether each of the following statements are true or false. If the statement is false, rewrite the given statement correctly.
If $A$ and $B$ are non-empty sets, then $A \times B$ is a non-empty set of ordered pairs $(x, y)$ such that $x \in A$ and $y \in B.$
If $A \times B=\{(a, x),(a, y),(b, x),(b, y)\} .$ Find $A$ and $B$
Let $A=\{1,2,3\}, B=\{3,4\}$ and $C=\{4,5,6\} .$ Find
$(A \times B) \cup(A \times C)$
If $A = \{2, 3, 5\}, B = \{2, 5, 6\},$ then $(A -B) × (A \cap B)$ is