If $A=\{-1,1\},$ find $A \times A \times A.$
If is known that for any non-empty set $A, A \times A \times A$ is defined as
$A \times A \times A=\{(a, b, c): a, b, c \in A\}$
It is given that $A=\{-1,1\}$
$\therefore A \times A \times A=\left\{\begin{array}{l}(-1-1,-1),(-1,-1,1),(-1,1,-1),(-1,1,1), \\ (1,-1,-1),(1,-1,1),(1,1,-1),(1,1,1)\end{array}\right\}$
If $G =\{7,8\}$ and $H =\{5,4,2\},$ find $G \times H$ and $H \times G$.
If $A = \{1, 2, 4\}, B = \{2, 4, 5\}, C = \{2, 5\},$ then $(A -B) × (B -C)$ is
If $A = \{ x:{x^2} - 5x + 6 = 0\} ,\,B = \{ 2,\,4\} ,\,C = \{ 4,\,5\} ,$ then $A \times (B \cap C)$ is
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If $P,Q$ and $R$ are subsets of a set $A$, then $R × (P^c \cup Q^c)^c =$