Let ${a_1},{a_2},{a_3}, \ldots $ be terms of $A.P.$  If $\frac{{{a_1} + {a_2} + \ldots + {a_p}}}{{{a_1} + {a_2} + \ldots + {a_q}}} = \frac{{{p^2}}}{{{q^2}}},p \ne q$ then $\frac{{{a_6}}}{{{a_{21}}}}$ equals

  • [AIEEE 2006]
  • A

    $\frac{{41}}{{11}}$

  • B

    $\frac{7}{2}$

  • C

    $\frac{2}{7}$

  • D

    $\frac{{11}}{{41}}$

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