Let $z$ =${i^{2i}}$ , then $|z|$ is (where $i$ =$\sqrt { - 1}$ )
Let $z$ =${i^{2i}}$ , then $|z|$ is (where $i$ =$\sqrt { - 1}$ )
- A
$1$
- B
${e^\pi }$
- C
${e^{ - \pi }}$
- D
${e^{\frac{\pi }{2}}}$
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- [IIT 1979]
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