If arg,z

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Question

(a) Since arg $z < 0$ i.e. -ve, we choose $arg\ z = -	heta$
where $	heta $ is $+ve$
$arg\  ( - z) = - [ + \pi - ( - 	heta )]$
$ = - \pi

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$\pi $

Vedclass · Answer

(a) Since arg $z < 0$ i.e. -ve, we choose $arg\ z = -	heta$
where $	heta $ is $+ve$
$arg\  ( - z) = - [ + \pi - ( - 	heta )]$
$ = - \pi - 	heta = 2\pi + ( - \pi - 	heta ) = \pi + arg(z)$
$ \Rightarrow \,arg\,( - z) - arg(z) = \pi .$

If $arg\,z < 0$ then $arg\,( - z) - arg\,(z)$ is equal to

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