9.Straight Line
hard

Let the equation of two sides of a triangle be $3x\,-\,2y\,+\,6\,=\,0$ and $4x\,+\,5y\,-\,20\,=\,0.$ If the orthocentre of this triangle is at $(1, 1),$ then the equation of its third side is

A

$122y\, - \,26x\, - 1675\, = \,0$

B

$26x\, + \,61y\, + \,1675\, = \,0$

C

$122y\, + \,26x\, + 1675\, = \,0$

D

$26x\, - \,122y\, - \,1675\, = \,0$

(JEE MAIN-2019)

Solution

Equation of $AB$ is $3x-2y+6=0$

Equation of $AC$ is $4x+5y-20=0$.

Equation of $BE$ is $2x+3y-5=0$

Equation of $CF$ is $5x-4y-1=0$

$ \Rightarrow $ Equation of  $BC$ is

$26x-122y=1675$

Standard 11
Mathematics

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