If coordinates of points A,, B,, C be (-1, 5),, (0, 0) and (2, 2) respectively and D be middle point

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9.Straight Line

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If the coordinates of the points $A,\, B,\, C$ be $(-1, 5),\, (0, 0)$ and $(2, 2)$ respectively and $D$ be the middle point of $BC$, then the equation of the perpendicular drawn from $B$ to the line $AD$ is

$x + 2y = 0$

$2x + y = 0$

$x - 2y = 0$

$2x - y = 0$

Solution

(c) Here $D(1, 1)$ therefore equation of line $AD$ is given by $2x + y – 3 = 0$. Thus the line perpendicular to $AD$ is $x – 2y + k = 0$and it passes through $B$, so $k = 0$. Hence required equation is $x – 2y = 0$.

Standard 11

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Solution

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