Light wave traveling in air along $x$-direction is given by $E _{ y }=540 \sin \pi \times 10^{4}( x - ct ) Vm ^{-1}$. Then, the peak value of magnetic field of wave will be $\dots \times 10^{-7}\,T$ (Given $c =3 \times 10^{8}\,ms ^{-1}$ )

The following travelling electromagnetic wave $E_x=0$ $E_y=E_0 \sin (k x+\omega t), E_z=-2 E_0 \sin (k x-\omega t)$ is

A point source of $100\,W$ emits light with $5 \%$ efficiency. At a distance of $5\,m$ from the source, the intensity produced by the electric field component is :

The energy associated with electric field is $(U_E)$ and with magnetic field is $(U_B)$ for an electromagnetic wave in free space. Then

A plane electromagnetic wave travels in free space along the $x -$ direction. The electric field component of the wave at a particular point of space and time is $E =6\; Vm^{-1}$ along $y -$ direction. Its corresponding magnetic filed component, $B$ would be

A plane electromagnetic wave propagating in $\mathrm{x}$-direction is described by

$\mathrm{E}_{\mathrm{y}}=\left(200\  \mathrm{Vm}^{-1}\right) \sin \left[1.5 \times 10^7 \mathrm{t}-0.05\  \mathrm{x}\right] \text {; }$

The intensity of the wave is :(Use $\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$ )