Gujarati
Hindi
10-2. Parabola, Ellipse, Hyperbola
normal

Locus of the feet of the perpendiculars drawn from either foci on a variable tangent to the hyperbola $16y^2 - 9x^2 = 1 $ is

A

$x^2 + y^2 = 9$

B

$x^2 + y^2 = 1/9$

C

$x^2 + y^2 =7/144$

D

$x^2 + y^2 = 1/16$

Solution

$\frac{{{y^2}}}{{1/16}}\,\, – \,\,\frac{{{x^2}}}{{1/9}}\,\, = \,\,1\,$
Locus will be the auxilary circle $x^2 + y^2 = 1/16$

Standard 11
Mathematics

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