Find the equation of the hyperbola satisfying the give conditions: Vertices $(\pm 2,\,0),$ foci $(\pm 3,\,0)$
Find the equation of the hyperbola satisfying the give conditions: Vertices $(\pm 2,\,0),$ foci $(\pm 3,\,0)$
Vertices $(\pm 2,\,0),$ foci $(±3,\,0)$
Here, the vertices are on the $x-$ axis.
Therefore, the equation of the hyperbola is of the form $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1$
since the vertices are $(\pm 2,\,0)$, $a =2$
since the foci are $(\pm 3,\,0)$, $c=3$
We know that $a^{2}+b^{2}=c^{2}$
$\therefore 2^{2}+b^{2}=3^{2}$
$b^{2}=9-4=5$
Thus, the equation of the hyperbola is $\frac{x^{2}}{4}-\frac{y^{2}}{5}=1$
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