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11.Thermodynamics
medium
Match List $I$ with List $II$ :
| List $I$ | List $II$ |
| $A$ Isothermal Process | $I$ Work done by the gas decreases internal energy |
| $B$ Adiabatic Process | $II$ No change in internal energy |
| $C$ Isochoric Process | $III$ The heat absorbed goes partly to increase internal energy and partly to do work |
| $D$ Isobaric Process | $IV$ No work is done on or by the gas |
Choose the correct answer from the options given below :
A
$A-II, B-I, C-III, D-IV$
B
$A-II, B-I, C-IV, D-III$
C
$A-I, B-II, C-IV, D-III$
D
$A-I, B-II, C-III, D-IV$
(JEE MAIN-2023)
Solution
$\Delta U = nC _{ v } \Delta T$
For isothermal process $T$ is constant
So $\Delta U =0$
$A \longrightarrow II$
Adiabatic process
$\Delta Q =0$
$\Delta Q =\Delta U +\Delta W$
$\quad \Delta U =-\Delta W$
Work done by gas is positive
So $\Delta U$ is negative
$B \longrightarrow I$
For Isochoric process $\Delta W =0$
$C \longrightarrow IV$
For Isobaric process
$\Delta W = P \Delta V \neq 0$
$\Delta U = nC _{ V } \Delta T \neq 0$
Heat absorbed goes partly to increase internal energy and partly do work.
Standard 11
Physics
