11.Thermodynamics
medium

During an adiabatic compression, $830\, J$ of work is done on $2\, moles$ of a diatomic ideal gas to reduce its volume by $50\%$. The change in its temperahture is nearly..... $K$ $(R\, = 8.3\, J\,K^{-1}\, mol^{-1} )$

A

$40$

B

$33$

C

$20$

D

$14$

(JEE MAIN-2014)

Solution

$Given:Work\,done,W=830J$

no, of moles of gas, $\mu =2$

For diatomic gas $\gamma  = 1.4$

Work done during an adiabatic change

$W = \frac{{\mu R\left( {{T_1} – {T_2}} \right)}}{{\gamma  – 1}}$

$ \Rightarrow 830 = \frac{{2 \times 8.3\left( {\Delta T} \right)}}{{1.4 – 1}} = \frac{{2 \times 8.3\left( {\Delta T} \right)}}{{0.4}}$

$ \Rightarrow \Delta T = \frac{{830 \times 0.4}}{{2 \times 8.3}} = 20\,K$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.