Mr. A has six children and atleast one child is a girl, then probability that Mr. A has $3$ boys and $3$ girls, is
Mr. A has six children and atleast one child is a girl, then probability that Mr. A has $3$ boys and $3$ girls, is
- A
$\frac{20}{63}$
- B
$\frac{1}{3}$
- C
$\frac{5}{11}$
- D
$\frac{1}{32}$
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