Gujarati
Hindi
14.Probability
normal

Mr. A has six children and atleast one child is a girl, then probability that Mr. A has $3$ boys and $3$ girls, is 

A

$\frac{20}{63}$

B

$\frac{1}{3}$

C

$\frac{5}{11}$

D

$\frac{1}{32}$

Solution

$\frac{{\left( {\frac{{6!}}{{3!3!}}} \right)}}{{{2^6} – 1}} = \frac{{20}}{{63}}$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.