Nitin bought some oranges at Rs., 40 a dozen and an equal number at ,30 a dozen. He sold them at Rs.

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7.Profit and Loss

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Nitin bought some oranges at $Rs.\, 40$ a dozen and an equal number at $\,30$ a dozen. He sold them at $Rs.\,45$ a dozen and made a profit of $\,480.$ The number of oranges, he bought, was

A

$48$

B

$60$

C

$72$

D

$84$

Solution

Let, the number of oranges bought be $₹x.$

$\therefore$ $C.P.$ of $x$ oranges $=\frac{x \times 40}{2 \times 12}+\frac{x \times 40}{2 \times 12}=₹ \frac{70 x}{24}$

$\therefore$ $S.P.$ of $x$ oranges $=\frac{x \times 45}{12}$

Now, according to the question,

$\frac{45 x}{12}-\frac{70 x}{12}=480$

$\Rightarrow \frac{90 x-70 x}{24}=480$

$x=\frac{480 \times 24}{20}=576=48 \times 12=48$ dozen

Standard 13

Quantitative Aptitude

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