On a new scale of temperature (which is linear) and called W, scale , freezing and boiling points of

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10-1.Thermometry, Thermal Expansion and Calorimetry

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On a new scale of temperature (which is linear) and called the $W\, scale$, the freezing and boiling points of water are $39\,^oW$ and $239\,^oW$ respectively. What will be th temperature on the new scale, corresponding to a temperature of $39\,^oC$ on the Celsius scale? ............ $^\circ \mathrm{W}$

A

$200$

B

$139$

C

$78$

D

$117$

Solution

$\frac{T_{(w)}^{1}-39}{239-39}=\frac{T^{\circ}(c)-0}{100-0}$

$\mathrm{T}_{(\mathrm{w})}^{1}=117\,^{\circ} \mathrm{W}$

Standard 11

Physics

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