Gujarati
8.Mechanical Properties of Solids
medium

On all the six surfaces of a unit cube, equal tensile force of $F$ is applied. The increase in length of each side will be ($Y =$ Young's modulus, $\sigma $= Poission's ratio)

A

$\frac{F}{{Y(1 - \sigma )}}$

B

$\frac{F}{{Y(1 + \sigma )}}$

C

$\frac{{F(1 - 2\sigma )}}{Y}$

D

$\frac{F}{{Y(1 + 2\sigma )}}$

Solution

(c) Tensile strain on each face$ = \frac{F}{Y}$

Lateral strain due to the other two forces acting on perpendicular faces$ = \frac{{ – 2\sigma F}}{Y}$

Total increase in length $ = (1 – 2\sigma )\frac{F}{Y}$

Standard 11
Physics

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