On her vacations Veena visits four cities $(A,\,B ,\, C$ and $D$ ) in a random order. What is the probability that she visits $A$ either first or second?
$S=\left\{\begin{array}{l} ABCD , ABDC , ACBD , ACDB , ADBC , ADCB , \\ BACD , BADC , BDAC , BDCA , BCAD , BCDA \\ CABD , CADB , CBDA , CBAD , CDAB , CDBA , \\ DABC , DACB , DBCA , DBAC , DCAB , DCBA \end{array}\right.$
Let $H$ be the event "she visits A either first or second"
$H=\left\{\begin{array}{r} ABCD , ABDC , ADBC , ACDB , ADBC , ADCB , \\ BACD , BADC , CABD , CADB , DABC , DACB ,\end{array}\right\}$
$So , n ( H )=12$
$P(H)=\frac{n(H)}{n(S)}$ $=\frac{12}{24}=\frac{1}{2}$
Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is
Three coins are tossed once. Find the probability of getting at most $2$ heads.
A fair coin is tossed four times, and a person win $\mathrm {Rs.}$ $1$ for each head and lose $\mathrm {Rs.}$ $1.50$ for each tail that turns up. From the sample space calculate how many different amounts of money you can have after four tosses and the probability of having each of these amounts.
The probability of a sure event is
Three coins are tossed once. Let $A$ denote the event ' three heads show ', $B$ denote the event ' two heads and one tail show ' , $C$ denote the event ' three tails show and $D$ denote the event 'a head shows on the first coin '. Which events are mutually exclusive ?