One card is drawn from each of two ordinary packs of 52 cards. probability that at least one of them

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14.Probability

easy

One card is drawn from each of two ordinary packs of $52$ cards. The probability that at least one of them is an ace of heart, is

A

$\frac{{103}}{{2704}}$

B

$\frac{1}{{2704}}$

C

$\frac{2}{{52}}$

D

$\frac{{2601}}{{2704}}$

Solution

(a) Required probability is $1 – P$ (no ace of heart)

$ = 1 – \frac{{51}}{{52}}.\frac{{51}}{{52}} = \frac{{(52 + 51)}}{{52\,.\,52}} = \frac{{103}}{{2704}}.$

Standard 11

Mathematics

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