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14.Probability
hard
Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is
A
$\frac{8}{9}$
B
$\frac{7}{9}$
C
$\frac{2}{9}$
D
$\frac{1}{9}$
(AIEEE-2005)
Solution
(d) For a particular house being selected , Probability $= \frac{1}{3}$
Probability (all the persons apply for the same house)
$ = \left( {\frac{1}{3} \times \frac{1}{3} \times \frac{1}{3}} \right)\,3 = \frac{1}{9}$.
Standard 11
Mathematics
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