14.Probability
hard

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is

A

$\frac{8}{9}$

B

$\frac{7}{9}$

C

$\frac{2}{9}$

D

$\frac{1}{9}$

(AIEEE-2005)

Solution

(d) For a particular house being selected , Probability $= \frac{1}{3}$

Probability (all the persons apply for the same house)

$ = \left( {\frac{1}{3} \times \frac{1}{3} \times \frac{1}{3}} \right)\,3 = \frac{1}{9}$.

Standard 11
Mathematics

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