One day on a spacecraft corresponds to 2 days on earth. speed of spacecraft relative to earth is

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11.Dual Nature of Radiation and matter

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One day on a spacecraft corresponds to $2$ days on the earth. The speed of the spacecraft relative to the earth is

A

$1.5 \times {10^8}m{s^{ - 1}}$

B

$2.1 \times {10^8}m{s^{ - 1}}$

C

$2.6 \times {10^8}m{s^{ - 1}}$

D

$5.2 \times {10^8}m{s^{ - 1}}$

Solution

(c) $T = \frac{{{T_0}}}{{{{[1 – ({v^2}/{c^2})]}^{1/2}}}}$

By substituting ${T_0} = 1$ day and $T = 2$ days we get

$v = 2.6 \times {10^8}\,m{s^{ – 1}}$

Standard 12

Physics

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