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10-1.Thermometry, Thermal Expansion and Calorimetry
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One kilogram of ice at $0°C$ is mixed with one kilogram of water at $80°C.$ The final temperature of the mixture is........ $^oC$
$($Take : specific heat of water$ = 4200\,J\,k{g^{ - 1}}\,{K^{ - 1}}$, latent heat of ice $ = 336\,kJ\,k{g^{ - 1}})$
A
$40$
B
$60$
C
$0$
D
$50$
Solution
(c) ${\theta _{{\rm{mix}}}} = \frac{{{m_W}{\theta _W} – \frac{{{m_{\,i}}{L_{\,i}}}}{{{c_W}}}}}{{{m_{\,i}} + {m_W}}}$
$\because \,{m_i} = {m_W}$ $\Rightarrow$ ${\theta _{mix}} = \frac{{{\theta _W} – \frac{{{L_i}}}{{{c_W}}}}}{2}$$ = \frac{{80 + 0 – \frac{{336}}{{4.2}}}}{2} = 0^\circ C$
Standard 11
Physics
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