Gujarati
Hindi
11.Thermodynamics
medium

One mole of an ideal gas $(\gamma  = 1.4)$ is adiabatically compressed so that its temperature rises from $27\,^oC$ to $35\,^oC$. The change in the internal energy of the gas is  .... $J$ (given $R = 8.3 \,J/mole/K$)

A

$-166$

B

$166$

C

$-168$

D

$168$

Solution

$\Delta \mathrm{U}=-\mathrm{W}=\frac{\mathrm{nR}\left(\mathrm{T}_{1}-\mathrm{T}_{2}\right)}{1-\mathrm{r}}=\frac{1 \times 8.3(-8)}{1-1.4}=166 \mathrm{J}$

Standard 11
Physics

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