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11.Thermodynamics
medium
One mole of an ideal gas $(\gamma = 1.4)$ is adiabatically compressed so that its temperature rises from $27\,^oC$ to $35\,^oC$. The change in the internal energy of the gas is .... $J$ (given $R = 8.3 \,J/mole/K$)
A
$-166$
B
$166$
C
$-168$
D
$168$
Solution
$\Delta \mathrm{U}=-\mathrm{W}=\frac{\mathrm{nR}\left(\mathrm{T}_{1}-\mathrm{T}_{2}\right)}{1-\mathrm{r}}=\frac{1 \times 8.3(-8)}{1-1.4}=166 \mathrm{J}$
Standard 11
Physics
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In Column$-I $ a graph and in Column$-II$ processes are given. Match them appropriately :
Column$-I $ | Column$-II $ |
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$(b)$ figure $(b)$ | $(ii)$ Isobaric process |
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hard