Gujarati
11.Thermodynamics
easy

One mole of helium is adiabatically expanded from its initial state $({P_i},{V_i},{T_i})$ to its final state $({P_f},{V_f},{T_f})$. The decrease in the internal energy associated with this expansion is equal to

A

${C_V}({T_i} - {T_f})$

B

${C_P}({T_i} - {T_f})$

C

$\frac{1}{2}({C_P} + {C_V})(Ti - {T_f})$

D

$({C_P} - {C_V})({T_i} - {T_f})$

Solution

(a)$\Delta U = \mu {C_V}\Delta T = 1 \times {C_V}({T_f} – {T_i}) = – \,{C_V}({T_i} – {T_f})$
==> |$\Delta U$| $= C_V (T_i -T_f)$

Standard 11
Physics

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