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11.Thermodynamics
easy
One mole of helium is adiabatically expanded from its initial state $({P_i},{V_i},{T_i})$ to its final state $({P_f},{V_f},{T_f})$. The decrease in the internal energy associated with this expansion is equal to
A
${C_V}({T_i} - {T_f})$
B
${C_P}({T_i} - {T_f})$
C
$\frac{1}{2}({C_P} + {C_V})(Ti - {T_f})$
D
$({C_P} - {C_V})({T_i} - {T_f})$
Solution
(a)$\Delta U = \mu {C_V}\Delta T = 1 \times {C_V}({T_f} – {T_i}) = – \,{C_V}({T_i} – {T_f})$
==> |$\Delta U$| $= C_V (T_i -T_f)$
Standard 11
Physics
Similar Questions
Match List $I$ with List $II$ :
List $I$ | List $II$ |
$A$ Isothermal Process | $I$ Work done by the gas decreases internal energy |
$B$ Adiabatic Process | $II$ No change in internal energy |
$C$ Isochoric Process | $III$ The heat absorbed goes partly to increase internal energy and partly to do work |
$D$ Isobaric Process | $IV$ No work is done on or by the gas |
Choose the correct answer from the options given below :