Out of 10 white, 9 black and 7 red balls, number of ways in which selection of one or more balls can

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6.Permutation and Combination

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Out of $10$ white, $9$ black and $7$ red balls, the number of ways in which selection of one or more balls can be made, is

A

$881$

B

$891$

C

$879$

D

$892$

Solution

(c) The required number of ways are

$(10 + 1)(9 + 1)(7 + 1) – 1 = 11 \times 10 \times 8 – 1 = 879$.

Standard 11

Mathematics

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