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14.Probability
easy
Out of $30$ consecutive numbers, $2$ are chosen at random. The probability that their sum is odd, is
A
$\frac{{14}}{{29}}$
B
$\frac{{16}}{{29}}$
C
$\frac{{15}}{{29}}$
D
$\frac{{10}}{{29}}$
Solution
(c) The total number of ways in which $2$ integers can be chosen from the given $30 $ integers is $^{30}{C_2}.$
The sum of the selected numbers is odd if exactly one of them is even and one is odd.
Favourable number of outcomes = $^{15}{C_1}{.^{15}}{C_1}$
$\therefore $ Required probability $ = \frac{{^{15}{C_1}.{\,^{15}}{C_1}}}{{^{30}{C_2}}} = \frac{{15}}{{29}}$.
Standard 11
Mathematics