Gujarati
14.Probability
easy

Out of $30$ consecutive numbers, $2$ are chosen at random. The probability that their sum is odd, is

A

$\frac{{14}}{{29}}$

B

$\frac{{16}}{{29}}$

C

$\frac{{15}}{{29}}$

D

$\frac{{10}}{{29}}$

Solution

(c) The total number of ways in which $2$ integers can be chosen from the given $30 $ integers is $^{30}{C_2}.$

The sum of the selected numbers is odd if exactly one of them is even and one is odd.

Favourable number of outcomes = $^{15}{C_1}{.^{15}}{C_1}$

$\therefore $ Required probability $ = \frac{{^{15}{C_1}.{\,^{15}}{C_1}}}{{^{30}{C_2}}} = \frac{{15}}{{29}}$.

Standard 11
Mathematics

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