Gujarati
Hindi
2.Motion in Straight Line
medium

Particle $A$ is moving along $x$-axis. At time $t=0$, it has velocity of $10\,m / s$ and acceleration $-4\,m / s ^2$. Particle $B$ has velocity of $20\,m / s$ and acceleration $-2\,m / s ^2$. Initially, both the particles are at origin. At time $t=2\,s$, distance between the two particles is $.............\,m$

A$24$
B$36$
C$20$
D$42$

Solution

(a)
At $2 s$
$x_A=10 \times 2-\frac{1}{2} \times 4 \times(2)^2=12\,m$
and $\quad x_B=20 \times 2-\frac{1}{2} \times 2 \times(2)^2$
$=36\,m$
$\therefore$ Distance between $A$ and $B$ at that instant is, $24\,m$.
Standard 11
Physics

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